Distance from Lake Oswego to Lacey
Distance from Lake Oswego to Lacey is 180 kilometers. This air travel distance is equal to 112 miles.
The air travel (bird fly) shortest distance between Lake Oswego and Lacey is 180 km or 112 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lake Oswego to Lacey, It takes 0.2 hours to arrive.
Lake Oswego
Lake Oswego is located in United States.
| GPS Coordinates (DMS) | 45° 25´ 14.4120'' N 122° 40´ 14.3400'' W |
|---|---|
| Latitude | 45.42067 |
| Longitude | -122.67065 |
| Altitude | 61 m |
| Country | United States |
Lake Oswego Distances to Cities
Lacey
Lacey is located in United States.
| GPS Coordinates | 47° 2´ 3.3360'' N 122° 49´ 23.4840'' W |
|---|---|
| Latitude | 47.03426 |
| Longitude | -122.82319 |
| Altitude | 62 m |
| Country | United States |
Lacey Distances to Cities
| Lacey | Distance |
|---|---|
| Distance from Lacey to Seatac | 61 km |
| Distance from Lacey to Lynnwood | 95 km |
| Distance from Lacey to Yakima | 183 km |
| Distance from Lacey to Spanaway | 31 km |
| Distance from Lacey to Silverdale | 69 km |