Distance from Lake Havasu City to Lawndale
Distance from Lake Havasu City to Lawndale is 377 kilometers. This air travel distance is equal to 234 miles.
The air travel (bird fly) shortest distance between Lake Havasu City and Lawndale is 377 km or 234 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lake Havasu City to Lawndale, It takes 0.42 hours to arrive.
Lake Havasu City
Lake Havasu City is located in United States.
| GPS Coordinates (DMS) | 34° 29´ 2.0400'' N 114° 19´ 20.8200'' W |
|---|---|
| Latitude | 34.48390 |
| Longitude | -114.32245 |
| Altitude | 228 m |
| Country | United States |
Lake Havasu City Distances to Cities
Lawndale
Lawndale is located in United States.
| GPS Coordinates | 33° 53´ 14.0640'' N 118° 21´ 9.2520'' W |
|---|---|
| Latitude | 33.88724 |
| Longitude | -118.35257 |
| Altitude | 19 m |
| Country | United States |
Lawndale Distances to Cities
| Lawndale | Distance |
|---|---|
| Distance from Lawndale to Los Angeles | 21 km |
| Distance from Lawndale to Lynwood | 14 km |
| Distance from Lawndale to Paso Robles | 288 km |
| Distance from Lawndale to Temecula | 120 km |
| Distance from Lawndale to Lompoc | 211 km |