Distance from Robertsganj to Khajuraho
Distance from Robertsganj to Khajurāho is 317 kilometers. This air travel distance is equal to 197 miles.
The air travel (bird fly) shortest distance between Robertsganj and Khajurāho is 317 km or 197 miles.
If you travel with an airplane (which has average speed of 560 miles) from Robertsganj to Khajuraho, It takes 0.35 hours to arrive.
Robertsganj
Robertsganj is located in India.
| GPS Coordinates (DMS) | 24° 41´ 20.0040'' N 83° 3´ 58.7520'' E |
|---|---|
| Latitude | 24.68889 |
| Longitude | 83.06632 |
| Altitude | 321 m |
| Country | India |
Robertsganj Distances to Cities
| Robertsganj | Distance |
|---|---|
| Distance from Robertsganj to Agra | 576 km |
| Distance from Robertsganj to Kolkata | 589 km |
| Distance from Robertsganj to Guna | 582 km |
| Distance from Robertsganj to Mathura | 622 km |
| Distance from Robertsganj to Ahmadpur | 917 km |
Khajuraho
Khajuraho is located in India.
| GPS Coordinates | 24° 50´ 52.0800'' N 79° 56´ 0.3840'' E |
|---|---|
| Latitude | 24.84780 |
| Longitude | 79.93344 |
| Altitude | 217 m |
| Country | India |
Khajurāho Distances to Cities
| Khajurāho | Distance |
|---|---|
| Distance from Khajuraho to Gomoh | 640 km |
| Distance from Khajuraho to Banswara | 576 km |
| Distance from Khajuraho to Faizabad | 307 km |
| Distance from Khajuraho to Farrukhabad | 284 km |
| Distance from Khajuraho to Bahraich | 345 km |