Distance from to
United States »
Jonesboro » Distances

Distance from Jonesboro to Searcy

Distance from Jonesboro to Searcy is 114 kilometers. This air travel distance is equal to 71 miles.

The air travel (bird fly) shortest distance between Jonesboro and Searcy is 114 km or 71 miles.

If you travel with an airplane (which has average speed of 560 miles) from Jonesboro to Searcy, It takes 0.13 hours to arrive.

Jonesboro

Jonesboro is located in United States.

GPS Coordinates (DMS)35° 50´ 32.2800'' N
90° 42´ 15.4080'' W
Latitude35.84230
Longitude-90.70428
Altitude96 m
CountryUnited States

Jonesboro Distances to Cities

JonesboroDistance
Distance from Jonesboro to Sandy Springs616 km
Distance from Jonesboro to Atlanta623 km
Distance from Jonesboro to Newnan606 km
Distance from Jonesboro to Nashville355 km
Distance from Jonesboro to Newport Beach2,498 km

Searcy

Searcy is located in United States.

GPS Coordinates35° 15´ 2.3040'' N
91° 44´ 10.5000'' W
Latitude35.25064
Longitude-91.73625
Altitude82 m
CountryUnited States

Searcy Distances to Cities

SearcyDistance
Distance from Searcy to Tulsa398 km
Distance from Searcy to Starkville334 km
Distance from Searcy to Farmers Branch541 km
Distance from Searcy to Dallas542 km
Distance from Searcy to Oklahoma City526 km

Map of Jonesboro

Map of Searcy