Distance from Jeffersonville to Reynoldsburg
Distance from Jeffersonville to Reynoldsburg is 314 kilometers. This air travel distance is equal to 195 miles.
The air travel (bird fly) shortest distance between Jeffersonville and Reynoldsburg is 314 km or 195 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jeffersonville to Reynoldsburg, It takes 0.35 hours to arrive.
Jeffersonville
Jeffersonville is located in United States.
| GPS Coordinates (DMS) | 38° 16´ 39.2520'' N 85° 44´ 13.8480'' W |
|---|---|
| Latitude | 38.27757 |
| Longitude | -85.73718 |
| Altitude | 138 m |
| Country | United States |
Jeffersonville Distances to Cities
Reynoldsburg
Reynoldsburg is located in United States.
| GPS Coordinates | 39° 57´ 17.2440'' N 82° 48´ 43.6320'' W |
|---|---|
| Latitude | 39.95479 |
| Longitude | -82.81212 |
| Altitude | 266 m |
| Country | United States |
Reynoldsburg Distances to Cities
| Reynoldsburg | Distance |
|---|---|
| Distance from Reynoldsburg to Jamaica Plain | 1,015 km |
| Distance from Reynoldsburg to Lincolnia | 504 km |
| Distance from Reynoldsburg to Boardman | 217 km |
| Distance from Reynoldsburg to Dublin Oh | 30 km |
| Distance from Reynoldsburg to Janesville | 601 km |