Distance from Herndon to Secaucus
Distance from Herndon to Secaucus is 349 kilometers. This air travel distance is equal to 217 miles.
The air travel (bird fly) shortest distance between Herndon and Secaucus is 349 km or 217 miles.
If you travel with an airplane (which has average speed of 560 miles) from Herndon to Secaucus, It takes 0.39 hours to arrive.
Herndon
Herndon is located in United States.
| GPS Coordinates (DMS) | 38° 58´ 10.3800'' N 77° 23´ 9.9600'' W |
|---|---|
| Latitude | 38.96955 |
| Longitude | -77.38610 |
| Altitude | 111 m |
| Country | United States |
Herndon Distances to Cities
| Herndon | Distance |
|---|---|
| Distance from Herndon to West New York | 352 km |
| Distance from Herndon to Chicago | 927 km |
| Distance from Herndon to Seaford | 383 km |
| Distance from Herndon to Piqua | 603 km |
| Distance from Herndon to Findlay | 582 km |
Secaucus
Secaucus is located in United States.
| GPS Coordinates | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |