Distance from Herndon to East Patchogue
Distance from Herndon to East Patchogue is 425 kilometers. This air travel distance is equal to 264 miles.
The air travel (bird fly) shortest distance between Herndon and East Patchogue is 425 km or 264 miles.
If you travel with an airplane (which has average speed of 560 miles) from Herndon to East Patchogue, It takes 0.47 hours to arrive.
Herndon
Herndon is located in United States.
| GPS Coordinates (DMS) | 38° 58´ 10.3800'' N 77° 23´ 9.9600'' W |
|---|---|
| Latitude | 38.96955 |
| Longitude | -77.38610 |
| Altitude | 111 m |
| Country | United States |
Herndon Distances to Cities
| Herndon | Distance |
|---|---|
| Distance from Herndon to West New York | 352 km |
| Distance from Herndon to Chicago | 927 km |
| Distance from Herndon to Seaford | 383 km |
| Distance from Herndon to Piqua | 603 km |
| Distance from Herndon to Findlay | 582 km |
East Patchogue
East Patchogue is located in United States.
| GPS Coordinates | 40° 46´ 1.3440'' N 72° 59´ 46.3920'' W |
|---|---|
| Latitude | 40.76704 |
| Longitude | -72.99622 |
| Altitude | 9 m |
| Country | United States |