Distance from Cockeysville to Herndon
Distance from Cockeysville to Herndon is 86 kilometers. This air travel distance is equal to 53 miles.
The air travel (bird fly) shortest distance between Cockeysville and Herndon is 86 km or 53 miles.
If you travel with an airplane (which has average speed of 560 miles) from Cockeysville to Herndon, It takes 0.1 hours to arrive.
Cockeysville
Cockeysville is located in United States.
| GPS Coordinates (DMS) | 39° 28´ 52.3920'' N 76° 38´ 37.8960'' W |
|---|---|
| Latitude | 39.48122 |
| Longitude | -76.64386 |
| Altitude | 91 m |
| Country | United States |
Cockeysville Distances to Cities
Herndon
Herndon is located in United States.
| GPS Coordinates | 38° 58´ 10.3800'' N 77° 23´ 9.9600'' W |
|---|---|
| Latitude | 38.96955 |
| Longitude | -77.38610 |
| Altitude | 111 m |
| Country | United States |
Herndon Distances to Cities
| Herndon | Distance |
|---|---|
| Distance from Herndon to West New York | 352 km |
| Distance from Herndon to Chicago | 927 km |
| Distance from Herndon to Seaford | 383 km |
| Distance from Herndon to Piqua | 603 km |
| Distance from Herndon to Findlay | 582 km |