Distance from Beltsville to Herndon
Distance from Beltsville to Herndon is 42 kilometers. This air travel distance is equal to 26 miles.
The air travel (bird fly) shortest distance between Beltsville and Herndon is 42 km or 26 miles.
If you travel with an airplane (which has average speed of 560 miles) from Beltsville to Herndon, It takes 0.05 hours to arrive.
Beltsville
Beltsville is located in United States.
| GPS Coordinates (DMS) | 39° 2´ 5.3880'' N 76° 54´ 26.8920'' W |
|---|---|
| Latitude | 39.03483 |
| Longitude | -76.90747 |
| Altitude | 43 m |
| Country | United States |
Beltsville Distances to Cities
Herndon
Herndon is located in United States.
| GPS Coordinates | 38° 58´ 10.3800'' N 77° 23´ 9.9600'' W |
|---|---|
| Latitude | 38.96955 |
| Longitude | -77.38610 |
| Altitude | 111 m |
| Country | United States |
Herndon Distances to Cities
| Herndon | Distance |
|---|---|
| Distance from Herndon to West New York | 352 km |
| Distance from Herndon to Chicago | 927 km |
| Distance from Herndon to Seaford | 383 km |
| Distance from Herndon to Piqua | 603 km |
| Distance from Herndon to Findlay | 582 km |