Distance from Grand Prairie to San Angelo
Distance from Grand Prairie to San Angelo is 354 kilometers. This air travel distance is equal to 220 miles.
The air travel (bird fly) shortest distance between Grand Prairie and San Angelo is 354 km or 220 miles.
If you travel with an airplane (which has average speed of 560 miles) from Grand Prairie to San Angelo, It takes 0.39 hours to arrive.
Grand Prairie
Grand Prairie is located in United States.
| GPS Coordinates (DMS) | 32° 44´ 45.4560'' N 96° 59´ 52.0080'' W |
|---|---|
| Latitude | 32.74596 |
| Longitude | -96.99778 |
| Altitude | 162 m |
| Country | United States |
Grand Prairie Distances to Cities
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |