Distance from Framingham to Sayreville Junction
Distance from Framingham to Sayreville Junction is 316 kilometers. This air travel distance is equal to 196 miles.
The air travel (bird fly) shortest distance between Framingham and Sayreville Junction is 316 km or 196 miles.
If you travel with an airplane (which has average speed of 560 miles) from Framingham to Sayreville Junction, It takes 0.35 hours to arrive.
Framingham
Framingham is located in United States.
| GPS Coordinates (DMS) | 42° 16´ 45.3360'' N 71° 24´ 58.2120'' W |
|---|---|
| Latitude | 42.27926 |
| Longitude | -71.41617 |
| Altitude | 54 m |
| Country | United States |
Framingham Distances to Cities
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |