Distance from Waverly to Faribault
Distance from Waverly to Faribault is 720 kilometers. This air travel distance is equal to 447 miles.
The air travel (bird fly) shortest distance between Waverly and Faribault is 720 km or 447 miles.
If you travel with an airplane (which has average speed of 560 miles) from Waverly to Faribault, It takes 0.8 hours to arrive.
Waverly
Waverly is located in United States.
| GPS Coordinates (DMS) | 42° 44´ 21.1200'' N 84° 37´ 14.9160'' W |
|---|---|
| Latitude | 42.73920 |
| Longitude | -84.62081 |
| Altitude | 264 m |
| Country | United States |
Waverly Distances to Cities
| Waverly | Distance |
|---|---|
| Distance from Waverly to Mankato | 775 km |
| Distance from Waverly to Omaha | 951 km |
| Distance from Waverly to Grand Island | 1,156 km |
| Distance from Waverly to Jamaica | 928 km |
| Distance from Waverly to Albert Lea | 718 km |
Faribault
Faribault is located in United States.
| GPS Coordinates | 44° 17´ 41.8560'' N 93° 16´ 7.7880'' W |
|---|---|
| Latitude | 44.29496 |
| Longitude | -93.26883 |
| Altitude | 304 m |
| Country | United States |