Distance from Faribault to Oshkosh
Distance from Faribault to Oshkosh is 379 kilometers. This air travel distance is equal to 235 miles.
The air travel (bird fly) shortest distance between Faribault and Oshkosh is 379 km or 235 miles.
If you travel with an airplane (which has average speed of 560 miles) from Faribault to Oshkosh, It takes 0.42 hours to arrive.
Faribault
Faribault is located in United States.
| GPS Coordinates (DMS) | 44° 17´ 41.8560'' N 93° 16´ 7.7880'' W |
|---|---|
| Latitude | 44.29496 |
| Longitude | -93.26883 |
| Altitude | 304 m |
| Country | United States |
Faribault Distances to Cities
Oshkosh
Oshkosh is located in United States.
| GPS Coordinates | 44° 1´ 28.9560'' N 88° 32´ 33.3960'' W |
|---|---|
| Latitude | 44.02471 |
| Longitude | -88.54261 |
| Altitude | 237 m |
| Country | United States |
Oshkosh Distances to Cities
| Oshkosh | Distance |
|---|---|
| Distance from Oshkosh to Sheboygan | 73 km |
| Distance from Oshkosh to Los Angeles | 2,780 km |
| Distance from Oshkosh to Florence Az | 2,324 km |
| Distance from Oshkosh to Phoenix | 2,347 km |
| Distance from Oshkosh to Tucson | 2,348 km |