Distance from Loves Park to Faribault
Distance from Loves Park to Faribault is 406 kilometers. This air travel distance is equal to 252 miles.
The air travel (bird fly) shortest distance between Loves Park and Faribault is 406 km or 252 miles.
If you travel with an airplane (which has average speed of 560 miles) from Loves Park to Faribault, It takes 0.45 hours to arrive.
Loves Park
Loves Park is located in United States.
| GPS Coordinates (DMS) | 42° 19´ 12.0720'' N 89° 3´ 29.3760'' W |
|---|---|
| Latitude | 42.32002 |
| Longitude | -89.05816 |
| Altitude | 223 m |
| Country | United States |
Loves Park Distances to Cities
| Loves Park | Distance |
|---|---|
| Distance from Loves Park to Grand Rapids | 287 km |
| Distance from Loves Park to Livonia | 470 km |
| Distance from Loves Park to Rochester Hills | 487 km |
| Distance from Loves Park to Jenison | 276 km |
| Distance from Loves Park to Zion | 102 km |
Faribault
Faribault is located in United States.
| GPS Coordinates | 44° 17´ 41.8560'' N 93° 16´ 7.7880'' W |
|---|---|
| Latitude | 44.29496 |
| Longitude | -93.26883 |
| Altitude | 304 m |
| Country | United States |