Distance from Faribault to Janesville
Distance from Faribault to Janesville is 388 kilometers. This air travel distance is equal to 241 miles.
The air travel (bird fly) shortest distance between Faribault and Janesville is 388 km or 241 miles.
If you travel with an airplane (which has average speed of 560 miles) from Faribault to Janesville, It takes 0.43 hours to arrive.
Faribault
Faribault is located in United States.
| GPS Coordinates (DMS) | 44° 17´ 41.8560'' N 93° 16´ 7.7880'' W |
|---|---|
| Latitude | 44.29496 |
| Longitude | -93.26883 |
| Altitude | 304 m |
| Country | United States |
Faribault Distances to Cities
Janesville
Janesville is located in United States.
| GPS Coordinates | 42° 40´ 58.0440'' N 89° 1´ 7.3920'' W |
|---|---|
| Latitude | 42.68279 |
| Longitude | -89.01872 |
| Altitude | 257 m |
| Country | United States |