Distance from Fall River to Secaucus
Distance from Fall River to Secaucus is 263 kilometers. This air travel distance is equal to 163 miles.
The air travel (bird fly) shortest distance between Fall River and Secaucus is 263 km or 163 miles.
If you travel with an airplane (which has average speed of 560 miles) from Fall River to Secaucus, It takes 0.29 hours to arrive.
Fall River
Fall River is located in United States.
| GPS Coordinates (DMS) | 41° 42´ 5.3640'' N 71° 9´ 18.1800'' W |
|---|---|
| Latitude | 41.70149 |
| Longitude | -71.15505 |
| Altitude | 12 m |
| Country | United States |
Fall River Distances to Cities
Secaucus
Secaucus is located in United States.
| GPS Coordinates | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |