Distance from Wellesley to East Patchogue
Distance from Wellesley to East Patchogue is 222 kilometers. This air travel distance is equal to 138 miles.
The air travel (bird fly) shortest distance between Wellesley and East Patchogue is 222 km or 138 miles.
If you travel with an airplane (which has average speed of 560 miles) from Wellesley to East Patchogue, It takes 0.25 hours to arrive.
Wellesley
Wellesley is located in United States.
| GPS Coordinates (DMS) | 42° 17´ 47.3640'' N 71° 17´ 33.2160'' W |
|---|---|
| Latitude | 42.29649 |
| Longitude | -71.29256 |
| Altitude | 44 m |
| Country | United States |
Wellesley Distances to Cities
| Wellesley | Distance |
|---|---|
| Distance from Wellesley to Scarsdale | 252 km |
| Distance from Wellesley to Westfield Ma | 122 km |
| Distance from Wellesley to Edison | 327 km |
| Distance from Wellesley to Elmira | 456 km |
| Distance from Wellesley to Woonsocket | 37 km |
East Patchogue
East Patchogue is located in United States.
| GPS Coordinates | 40° 46´ 1.3440'' N 72° 59´ 46.3920'' W |
|---|---|
| Latitude | 40.76704 |
| Longitude | -72.99622 |
| Altitude | 9 m |
| Country | United States |