Distance from Secaucus to East Patchogue
Distance from Secaucus to East Patchogue is 90 kilometers. This air travel distance is equal to 56 miles.
The air travel (bird fly) shortest distance between Secaucus and East Patchogue is 90 km or 56 miles.
If you travel with an airplane (which has average speed of 560 miles) from Secaucus to East Patchogue, It takes 0.1 hours to arrive.
Secaucus
Secaucus is located in United States.
| GPS Coordinates (DMS) | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |
Secaucus Distances to Cities
East Patchogue
East Patchogue is located in United States.
| GPS Coordinates | 40° 46´ 1.3440'' N 72° 59´ 46.3920'' W |
|---|---|
| Latitude | 40.76704 |
| Longitude | -72.99622 |
| Altitude | 9 m |
| Country | United States |