Distance from Dubrovnik to San Giuseppe Vesuviano
Distance from Dubrovnik to San Giuseppe Vesuviano is 360 kilometers. This air travel distance is equal to 224 miles.
The air travel (bird fly) shortest distance between Dubrovnik and San Giuseppe Vesuviano is 360 km or 224 miles.
If you travel with an airplane (which has average speed of 560 miles) from Dubrovnik to San Giuseppe Vesuviano, It takes 0.4 hours to arrive.
Dubrovnik
Dubrovnik is located in Croatia.
GPS Coordinates (DMS) | 42° 38´ 53.0520'' N 18° 5´ 31.7760'' E |
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Latitude | 42.64807 |
Longitude | 18.09216 |
Altitude | 52 m |
Country | Croatia |
Dubrovnik Distances to Cities
Dubrovnik | Distance |
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Distance from Dubrovnik to Bari | 199 km |
Distance from Dubrovnik to Rome | 468 km |
Distance from Dubrovnik to Ancona | 388 km |
Distance from Dubrovnik to Rimini | 475 km |
Distance from Dubrovnik to Civitavecchia | 522 km |
San Giuseppe Vesuviano
San Giuseppe Vesuviano is located in Italy.
GPS Coordinates | 40° 49´ 49.2240'' N 14° 30´ 12.3120'' E |
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Latitude | 40.83034 |
Longitude | 14.50342 |
Altitude | 106 m |
Country | Italy |