Distance from Deerfield to Norton Shores
Distance from Deerfield to Norton Shores is 171 kilometers. This air travel distance is equal to 106 miles.
The air travel (bird fly) shortest distance between Deerfield and Norton Shores is 171 km or 106 miles.
If you travel with an airplane (which has average speed of 560 miles) from Deerfield to Norton Shores, It takes 0.19 hours to arrive.
Deerfield
Deerfield is located in United States.
| GPS Coordinates (DMS) | 42° 10´ 16.1040'' N 87° 50´ 40.2360'' W |
|---|---|
| Latitude | 42.17114 |
| Longitude | -87.84451 |
| Altitude | 214 m |
| Country | United States |
Deerfield Distances to Cities
Norton Shores
Norton Shores is located in United States.
| GPS Coordinates | 43° 10´ 8.0400'' N 86° 15´ 50.2200'' W |
|---|---|
| Latitude | 43.16890 |
| Longitude | -86.26395 |
| Altitude | 191 m |
| Country | United States |
Norton Shores Distances to Cities
| Norton Shores | Distance |
|---|---|
| Distance from Norton Shores to Santa Fe | 1,880 km |
| Distance from Norton Shores to Avon Lake | 395 km |
| Distance from Norton Shores to Milwaukee | 134 km |
| Distance from Norton Shores to Ashtabula | 472 km |
| Distance from Norton Shores to South Euclid | 432 km |