Distance from Cranford to Secaucus
Distance from Cranford to Secaucus is 25 kilometers. This air travel distance is equal to 16 miles.
The air travel (bird fly) shortest distance between Cranford and Secaucus is 25 km or 16 miles.
If you travel with an airplane (which has average speed of 560 miles) from Cranford to Secaucus, It takes 0.03 hours to arrive.
Cranford
Cranford is located in United States.
| GPS Coordinates (DMS) | 40° 39´ 30.3840'' N 74° 17´ 58.5240'' W |
|---|---|
| Latitude | 40.65844 |
| Longitude | -74.29959 |
| Altitude | 24 m |
| Country | United States |
Cranford Distances to Cities
Secaucus
Secaucus is located in United States.
| GPS Coordinates | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |