Distance from Cranford to Sayreville Junction
Distance from Cranford to Sayreville Junction is 22 kilometers. This air travel distance is equal to 14 miles.
The air travel (bird fly) shortest distance between Cranford and Sayreville Junction is 22 km or 14 miles.
If you travel with an airplane (which has average speed of 560 miles) from Cranford to Sayreville Junction, It takes 0.02 hours to arrive.
Cranford
Cranford is located in United States.
| GPS Coordinates (DMS) | 40° 39´ 30.3840'' N 74° 17´ 58.5240'' W |
|---|---|
| Latitude | 40.65844 |
| Longitude | -74.29959 |
| Altitude | 24 m |
| Country | United States |
Cranford Distances to Cities
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |