Distance from Clemmons to Hayesville
Distance from Clemmons to Hayesville is 3,699 kilometers. This air travel distance is equal to 2,298 miles.
The air travel (bird fly) shortest distance between Clemmons and Hayesville is 3,699 km or 2,298 miles.
If you travel with an airplane (which has average speed of 560 miles) from Clemmons to Hayesville, It takes 4.1 hours to arrive.
Clemmons
Clemmons is located in United States.
| GPS Coordinates (DMS) | 36° 1´ 17.5080'' N 80° 22´ 55.2000'' W |
|---|---|
| Latitude | 36.02153 |
| Longitude | -80.38200 |
| Altitude | 255 m |
| Country | United States |
Clemmons Distances to Cities
Hayesville
Hayesville is located in United States.
| GPS Coordinates | 44° 59´ 9.4200'' N 122° 58´ 58.3320'' W |
|---|---|
| Latitude | 44.98595 |
| Longitude | -122.98287 |
| Altitude | 55 m |
| Country | United States |
Hayesville Distances to Cities
| Hayesville | Distance |
|---|---|
| Distance from Hayesville to Woodburn | 20 km |
| Distance from Hayesville to Kailua | 4,111 km |
| Distance from Hayesville to Makakilo | 4,140 km |
| Distance from Hayesville to Clinton Ut | 987 km |
| Distance from Hayesville to Bonney Lake | 251 km |