Distance from Cleburne to San Angelo
Distance from Cleburne to San Angelo is 305 kilometers. This air travel distance is equal to 190 miles.
The air travel (bird fly) shortest distance between Cleburne and San Angelo is 305 km or 190 miles.
If you travel with an airplane (which has average speed of 560 miles) from Cleburne to San Angelo, It takes 0.34 hours to arrive.
Cleburne
Cleburne is located in United States.
| GPS Coordinates (DMS) | 32° 20´ 51.5040'' N 97° 23´ 12.0480'' W |
|---|---|
| Latitude | 32.34764 |
| Longitude | -97.38668 |
| Altitude | 240 m |
| Country | United States |
Cleburne Distances to Cities
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |