Distance from Citrus Heights to Oakley
Distance from Citrus Heights to Oakley is 87 kilometers. This air travel distance is equal to 54 miles.
The air travel (bird fly) shortest distance between Citrus Heights and Oakley is 87 km or 54 miles.
If you travel with an airplane (which has average speed of 560 miles) from Citrus Heights to Oakley, It takes 0.1 hours to arrive.
Citrus Heights
Citrus Heights is located in United States.
| GPS Coordinates (DMS) | 38° 42´ 25.6320'' N 121° 16´ 51.8160'' W |
|---|---|
| Latitude | 38.70712 |
| Longitude | -121.28106 |
| Altitude | 52 m |
| Country | United States |
Citrus Heights Distances to Cities
Oakley
Oakley is located in United States.
| GPS Coordinates | 37° 59´ 50.7120'' N 121° 42´ 44.8200'' W |
|---|---|
| Latitude | 37.99742 |
| Longitude | -121.71245 |
| Altitude | 5 m |
| Country | United States |