Distance from Severna Park to Christiansburg
Distance from Severna Park to Christiansburg is 401 kilometers. This air travel distance is equal to 249 miles.
The air travel (bird fly) shortest distance between Severna Park and Christiansburg is 401 km or 249 miles.
If you travel with an airplane (which has average speed of 560 miles) from Severna Park to Christiansburg, It takes 0.44 hours to arrive.
Severna Park
Severna Park is located in United States.
| GPS Coordinates (DMS) | 39° 4´ 13.4040'' N 76° 32´ 42.8640'' W |
|---|---|
| Latitude | 39.07039 |
| Longitude | -76.54524 |
| Altitude | 14 m |
| Country | United States |
Severna Park Distances to Cities
Christiansburg
Christiansburg is located in United States.
| GPS Coordinates | 37° 7´ 47.4600'' N 80° 24´ 32.1840'' W |
|---|---|
| Latitude | 37.12985 |
| Longitude | -80.40894 |
| Altitude | 637 m |
| Country | United States |
Christiansburg Distances to Cities
| Christiansburg | Distance |
|---|---|
| Distance from Christiansburg to Virginia Beach | 396 km |
| Distance from Christiansburg to Los Angeles | 3,423 km |
| Distance from Christiansburg to Roanoke | 44 km |
| Distance from Christiansburg to Elko | 3,070 km |
| Distance from Christiansburg to Tucson | 2,837 km |