Distance from Pleasure Ridge Park to Christiansburg
Distance from Pleasure Ridge Park to Christiansburg is 494 kilometers. This air travel distance is equal to 307 miles.
The air travel (bird fly) shortest distance between Pleasure Ridge Park and Christiansburg is 494 km or 307 miles.
If you travel with an airplane (which has average speed of 560 miles) from Pleasure Ridge Park to Christiansburg, It takes 0.55 hours to arrive.
Pleasure Ridge Park
Pleasure Ridge Park is located in United States.
| GPS Coordinates (DMS) | 38° 8´ 43.2600'' N 85° 51´ 29.8800'' W |
|---|---|
| Latitude | 38.14535 |
| Longitude | -85.85830 |
| Altitude | 139 m |
| Country | United States |
Pleasure Ridge Park Distances to Cities
Christiansburg
Christiansburg is located in United States.
| GPS Coordinates | 37° 7´ 47.4600'' N 80° 24´ 32.1840'' W |
|---|---|
| Latitude | 37.12985 |
| Longitude | -80.40894 |
| Altitude | 637 m |
| Country | United States |
Christiansburg Distances to Cities
| Christiansburg | Distance |
|---|---|
| Distance from Christiansburg to Virginia Beach | 396 km |
| Distance from Christiansburg to Los Angeles | 3,423 km |
| Distance from Christiansburg to Roanoke | 44 km |
| Distance from Christiansburg to Elko | 3,070 km |
| Distance from Christiansburg to Tucson | 2,837 km |