Distance from Langley Park to Christiansburg
Distance from Langley Park to Christiansburg is 365 kilometers. This air travel distance is equal to 227 miles.
The air travel (bird fly) shortest distance between Langley Park and Christiansburg is 365 km or 227 miles.
If you travel with an airplane (which has average speed of 560 miles) from Langley Park to Christiansburg, It takes 0.41 hours to arrive.
Langley Park
Langley Park is located in United States.
| GPS Coordinates (DMS) | 38° 59´ 19.3920'' N 76° 58´ 52.8960'' W |
|---|---|
| Latitude | 38.98872 |
| Longitude | -76.98136 |
| Altitude | 49 m |
| Country | United States |
Langley Park Distances to Cities
Christiansburg
Christiansburg is located in United States.
| GPS Coordinates | 37° 7´ 47.4600'' N 80° 24´ 32.1840'' W |
|---|---|
| Latitude | 37.12985 |
| Longitude | -80.40894 |
| Altitude | 637 m |
| Country | United States |
Christiansburg Distances to Cities
| Christiansburg | Distance |
|---|---|
| Distance from Christiansburg to Virginia Beach | 396 km |
| Distance from Christiansburg to Los Angeles | 3,423 km |
| Distance from Christiansburg to Roanoke | 44 km |
| Distance from Christiansburg to Elko | 3,070 km |
| Distance from Christiansburg to Tucson | 2,837 km |