Distance from Beltsville to Christiansburg
Distance from Beltsville to Christiansburg is 373 kilometers. This air travel distance is equal to 232 miles.
The air travel (bird fly) shortest distance between Beltsville and Christiansburg is 373 km or 232 miles.
If you travel with an airplane (which has average speed of 560 miles) from Beltsville to Christiansburg, It takes 0.41 hours to arrive.
Beltsville
Beltsville is located in United States.
| GPS Coordinates (DMS) | 39° 2´ 5.3880'' N 76° 54´ 26.8920'' W |
|---|---|
| Latitude | 39.03483 |
| Longitude | -76.90747 |
| Altitude | 43 m |
| Country | United States |
Beltsville Distances to Cities
Christiansburg
Christiansburg is located in United States.
| GPS Coordinates | 37° 7´ 47.4600'' N 80° 24´ 32.1840'' W |
|---|---|
| Latitude | 37.12985 |
| Longitude | -80.40894 |
| Altitude | 637 m |
| Country | United States |
Christiansburg Distances to Cities
| Christiansburg | Distance |
|---|---|
| Distance from Christiansburg to Virginia Beach | 396 km |
| Distance from Christiansburg to Los Angeles | 3,423 km |
| Distance from Christiansburg to Roanoke | 44 km |
| Distance from Christiansburg to Elko | 3,070 km |
| Distance from Christiansburg to Tucson | 2,837 km |