Distance from Ceres to Oakley
Distance from Ceres to Oakley is 80 kilometers. This air travel distance is equal to 50 miles.
The air travel (bird fly) shortest distance between Ceres and Oakley is 80 km or 50 miles.
If you travel with an airplane (which has average speed of 560 miles) from Ceres to Oakley, It takes 0.09 hours to arrive.
Ceres
Ceres is located in United States.
| GPS Coordinates (DMS) | 37° 35´ 41.7480'' N 120° 57´ 27.7560'' W |
|---|---|
| Latitude | 37.59493 |
| Longitude | -120.95771 |
| Altitude | 28 m |
| Country | United States |
Ceres Distances to Cities
Oakley
Oakley is located in United States.
| GPS Coordinates | 37° 59´ 50.7120'' N 121° 42´ 44.8200'' W |
|---|---|
| Latitude | 37.99742 |
| Longitude | -121.71245 |
| Altitude | 5 m |
| Country | United States |