Distance from Brentwood Estates to Sandusky
Distance from Brentwood Estates to Sandusky is 698 kilometers. This air travel distance is equal to 434 miles.
The air travel (bird fly) shortest distance between Brentwood Estates and Sandusky is 698 km or 434 miles.
If you travel with an airplane (which has average speed of 560 miles) from Brentwood Estates to Sandusky, It takes 0.77 hours to arrive.
Brentwood Estates
Brentwood Estates is located in United States.
GPS Coordinates (DMS) | 36° 1´ 30.2160'' N 86° 46´ 45.0120'' W |
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Latitude | 36.02506 |
Longitude | -86.77917 |
Altitude | 227 m |
Country | United States |
Brentwood Estates Distances to Cities
Brentwood Estates | Distance |
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Distance from Brentwood Estates to Chicago | 651 km |
Distance from Brentwood Estates to Lynbrook | 1,254 km |
Distance from Brentwood Estates to Bel Air North | 996 km |
Distance from Brentwood Estates to Penn Hills | 784 km |
Distance from Brentwood Estates to Loves Park | 726 km |
Sandusky
Sandusky is located in United States.
GPS Coordinates | 41° 26´ 56.1840'' N 82° 42´ 28.6560'' W |
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Latitude | 41.44894 |
Longitude | -82.70796 |
Altitude | 183 m |
Country | United States |
Sandusky Distances to Cities
Sandusky | Distance |
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Distance from Sandusky to South Euclid | 100 km |
Distance from Sandusky to Waukesha | 488 km |
Distance from Sandusky to Pittsburgh | 254 km |
Distance from Sandusky to Tucson | 2,702 km |
Distance from Sandusky to Janesville | 540 km |