Distance from Boynton Beach to Seminole
Distance from Boynton Beach to Seminole is 307 kilometers. This air travel distance is equal to 191 miles.
The air travel (bird fly) shortest distance between Boynton Beach and Seminole is 307 km or 191 miles.
If you travel with an airplane (which has average speed of 560 miles) from Boynton Beach to Seminole, It takes 0.34 hours to arrive.
Boynton Beach
Boynton Beach is located in United States.
| GPS Coordinates (DMS) | 26° 31´ 31.2600'' N 80° 3´ 59.1480'' W |
|---|---|
| Latitude | 26.52535 |
| Longitude | -80.06643 |
| Altitude | 11 m |
| Country | United States |
Boynton Beach Distances to Cities
Seminole
Seminole is located in United States.
| GPS Coordinates | 27° 50´ 23.1000'' N 82° 47´ 28.3560'' W |
|---|---|
| Latitude | 27.83975 |
| Longitude | -82.79121 |
| Altitude | 16 m |
| Country | United States |