Distance from Boynton Beach to Florida Ridge
Distance from Boynton Beach to Florida Ridge is 121 kilometers. This air travel distance is equal to 75 miles.
The air travel (bird fly) shortest distance between Boynton Beach and Florida Ridge is 121 km or 75 miles.
If you travel with an airplane (which has average speed of 560 miles) from Boynton Beach to Florida Ridge, It takes 0.13 hours to arrive.
Boynton Beach
Boynton Beach is located in United States.
| GPS Coordinates (DMS) | 26° 31´ 31.2600'' N 80° 3´ 59.1480'' W |
|---|---|
| Latitude | 26.52535 |
| Longitude | -80.06643 |
| Altitude | 11 m |
| Country | United States |
Boynton Beach Distances to Cities
Florida Ridge
Florida Ridge is located in United States.
| GPS Coordinates | 27° 34´ 49.1160'' N 80° 23´ 12.1920'' W |
|---|---|
| Latitude | 27.58031 |
| Longitude | -80.38672 |
| Altitude | 8 m |
| Country | United States |
Florida Ridge Distances to Cities
| Florida Ridge | Distance |
|---|---|
| Distance from Florida Ridge to Miami | 201 km |
| Distance from Florida Ridge to Ashburn | 1,300 km |
| Distance from Florida Ridge to Fort Myers | 179 km |
| Distance from Florida Ridge to Placentia | 3,637 km |
| Distance from Florida Ridge to Plant City | 177 km |