Distance from Bloomfield to Sayreville Junction
Distance from Bloomfield to Sayreville Junction is 40 kilometers. This air travel distance is equal to 25 miles.
The air travel (bird fly) shortest distance between Bloomfield and Sayreville Junction is 40 km or 25 miles.
If you travel with an airplane (which has average speed of 560 miles) from Bloomfield to Sayreville Junction, It takes 0.04 hours to arrive.
Bloomfield
Bloomfield is located in United States.
| GPS Coordinates (DMS) | 40° 48´ 24.3720'' N 74° 11´ 7.5120'' W |
|---|---|
| Latitude | 40.80677 |
| Longitude | -74.18542 |
| Altitude | 51 m |
| Country | United States |
Bloomfield Distances to Cities
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |