Distance from Isabel to Binalbagan
Distance from Isabel to Binalbagan is 4,500 kilometers. This air travel distance is equal to 2,796 miles.
The air travel (bird fly) shortest distance between Isabel and Binalbagan is 4,500 km or 2,796 miles.
If you travel with an airplane (which has average speed of 560 miles) from Isabel to Binalbagan, It takes 4.99 hours to arrive.
Isabel
Isabel is located in Solomon Islands.
| GPS Coordinates (DMS) | 8° 3´ 33.2640'' S 159° 8´ 40.9560'' E |
|---|---|
| Latitude | -8.05924 |
| Longitude | 159.14471 |
| Altitude | 146 m |
| Country | Solomon Islands |
Isabel Distances to Cities
| Isabel | Distance |
|---|---|
| Distance from Isabel to Cebu City | 4,404 km |
| Distance from Isabel to Manila | 4,902 km |
| Distance from Isabel to Roxas City | 4,578 km |
| Distance from Isabel to Calbayog City | 4,424 km |
| Distance from Isabel to Bacolod City | 4,513 km |
Binalbagan
Binalbagan is located in Philippines.
| GPS Coordinates | 10° 11´ 41.2800'' N 122° 51´ 29.1600'' E |
|---|---|
| Latitude | 10.19480 |
| Longitude | 122.85810 |
| Altitude | 11 m |
| Country | Philippines |