Distance from Sayreville Junction to Bay Shore
Distance from Sayreville Junction to Bay Shore is 96 kilometers. This air travel distance is equal to 60 miles.
The air travel (bird fly) shortest distance between Sayreville Junction and Bay Shore is 96 km or 60 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sayreville Junction to Bay Shore, It takes 0.11 hours to arrive.
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates (DMS) | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |
Sayreville Junction Distances to Cities
Bay Shore
Bay Shore is located in United States.
| GPS Coordinates | 40° 43´ 30.3600'' N 73° 14´ 43.4040'' W |
|---|---|
| Latitude | 40.72510 |
| Longitude | -73.24539 |
| Altitude | 9 m |
| Country | United States |