Distance from Searcy to Bartlesville
Distance from Searcy to Bartlesville is 417 kilometers. This air travel distance is equal to 259 miles.
The air travel (bird fly) shortest distance between Searcy and Bartlesville is 417 km or 259 miles.
If you travel with an airplane (which has average speed of 560 miles) from Searcy to Bartlesville, It takes 0.46 hours to arrive.
Searcy
Searcy is located in United States.
| GPS Coordinates (DMS) | 35° 15´ 2.3040'' N 91° 44´ 10.5000'' W |
|---|---|
| Latitude | 35.25064 |
| Longitude | -91.73625 |
| Altitude | 82 m |
| Country | United States |
Searcy Distances to Cities
| Searcy | Distance |
|---|---|
| Distance from Searcy to Tulsa | 398 km |
| Distance from Searcy to Starkville | 334 km |
| Distance from Searcy to Farmers Branch | 541 km |
| Distance from Searcy to Dallas | 542 km |
| Distance from Searcy to Oklahoma City | 526 km |
Bartlesville
Bartlesville is located in United States.
| GPS Coordinates | 36° 44´ 50.3160'' N 95° 58´ 50.9520'' W |
|---|---|
| Latitude | 36.74731 |
| Longitude | -95.98082 |
| Altitude | 217 m |
| Country | United States |