Distance from Austintown to Parma Heights
Distance from Austintown to Parma Heights is 89 kilometers. This air travel distance is equal to 55 miles.
The air travel (bird fly) shortest distance between Austintown and Parma Heights is 89 km or 55 miles.
If you travel with an airplane (which has average speed of 560 miles) from Austintown to Parma Heights, It takes 0.1 hours to arrive.
Austintown
Austintown is located in United States.
| GPS Coordinates (DMS) | 41° 6´ 6.1920'' N 80° 45´ 52.2720'' W |
|---|---|
| Latitude | 41.10172 |
| Longitude | -80.76452 |
| Altitude | 345 m |
| Country | United States |
Austintown Distances to Cities
Parma Heights
Parma Heights is located in United States.
| GPS Coordinates | 41° 23´ 24.1800'' N 81° 45´ 34.4880'' W |
|---|---|
| Latitude | 41.39005 |
| Longitude | -81.75958 |
| Altitude | 262 m |
| Country | United States |
Parma Heights Distances to Cities
| Parma Heights | Distance |
|---|---|
| Distance from Parma Heights to Solon | 27 km |
| Distance from Parma Heights to Sylvania | 167 km |
| Distance from Parma Heights to Neenah | 630 km |
| Distance from Parma Heights to Youngstown | 98 km |
| Distance from Parma Heights to Westlake | 15 km |