Distance from Cleveland Heights to Austintown
Distance from Cleveland Heights to Austintown is 81 kilometers. This air travel distance is equal to 50 miles.
The air travel (bird fly) shortest distance between Cleveland Heights and Austintown is 81 km or 50 miles.
If you travel with an airplane (which has average speed of 560 miles) from Cleveland Heights to Austintown, It takes 0.09 hours to arrive.
Cleveland Heights
Cleveland Heights is located in United States.
| GPS Coordinates (DMS) | 41° 31´ 12.1800'' N 81° 33´ 22.4640'' W |
|---|---|
| Latitude | 41.52005 |
| Longitude | -81.55624 |
| Altitude | 288 m |
| Country | United States |
Cleveland Heights Distances to Cities
| Cleveland Heights | Distance |
|---|---|
| Distance from Cleveland Heights to Lemont | 538 km |
| Distance from Cleveland Heights to Libertyville | 537 km |
| Distance from Cleveland Heights to Avon | 41 km |
| Distance from Cleveland Heights to Elmhurst | 533 km |
| Distance from Cleveland Heights to Redford | 173 km |
Austintown
Austintown is located in United States.
| GPS Coordinates | 41° 6´ 6.1920'' N 80° 45´ 52.2720'' W |
|---|---|
| Latitude | 41.10172 |
| Longitude | -80.76452 |
| Altitude | 345 m |
| Country | United States |