Distance from Asheboro to Petersburg
Distance from Asheboro to Petersburg is 274 kilometers. This air travel distance is equal to 170 miles.
The air travel (bird fly) shortest distance between Asheboro and Petersburg is 274 km or 170 miles.
If you travel with an airplane (which has average speed of 560 miles) from Asheboro to Petersburg, It takes 0.3 hours to arrive.
Asheboro
Asheboro is located in United States.
| GPS Coordinates (DMS) | 35° 42´ 28.4760'' N 79° 48´ 49.1040'' W |
|---|---|
| Latitude | 35.70791 |
| Longitude | -79.81364 |
| Altitude | 256 m |
| Country | United States |
Asheboro Distances to Cities
| Asheboro | Distance |
|---|---|
| Distance from Asheboro to Winston Salem | 58 km |
| Distance from Asheboro to Carrboro | 70 km |
| Distance from Asheboro to Virginia Beach | 367 km |
| Distance from Asheboro to Houston | 1,597 km |
| Distance from Asheboro to Lumberton | 141 km |
Petersburg
Petersburg is located in United States.
| GPS Coordinates | 37° 13´ 40.5480'' N 77° 24´ 6.9480'' W |
|---|---|
| Latitude | 37.22793 |
| Longitude | -77.40193 |
| Altitude | 22 m |
| Country | United States |
Petersburg Distances to Cities
| Petersburg | Distance |
|---|---|
| Distance from Petersburg to Virginia Beach | 133 km |
| Distance from Petersburg to Beckley | 340 km |
| Distance from Petersburg to Staunton | 179 km |
| Distance from Petersburg to Roanoke | 225 km |
| Distance from Petersburg to Pampa | 2,117 km |