Distance from Arlington Heights to Sandusky
Distance from Arlington Heights to Sandusky is 444 kilometers. This air travel distance is equal to 276 miles.
The air travel (bird fly) shortest distance between Arlington Heights and Sandusky is 444 km or 276 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arlington Heights to Sandusky, It takes 0.49 hours to arrive.
Arlington Heights
Arlington Heights is located in United States.
| GPS Coordinates (DMS) | 42° 5´ 18.0960'' N 87° 58´ 50.2680'' W |
|---|---|
| Latitude | 42.08836 |
| Longitude | -87.98063 |
| Altitude | 219 m |
| Country | United States |
Arlington Heights Distances to Cities
Sandusky
Sandusky is located in United States.
| GPS Coordinates | 41° 26´ 56.1840'' N 82° 42´ 28.6560'' W |
|---|---|
| Latitude | 41.44894 |
| Longitude | -82.70796 |
| Altitude | 183 m |
| Country | United States |
Sandusky Distances to Cities
| Sandusky | Distance |
|---|---|
| Distance from Sandusky to South Euclid | 100 km |
| Distance from Sandusky to Waukesha | 488 km |
| Distance from Sandusky to Pittsburgh | 254 km |
| Distance from Sandusky to Tucson | 2,702 km |
| Distance from Sandusky to Janesville | 540 km |