Distance from Arbutus to Sayreville Junction
Distance from Arbutus to Sayreville Junction is 243 kilometers. This air travel distance is equal to 151 miles.
The air travel (bird fly) shortest distance between Arbutus and Sayreville Junction is 243 km or 151 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arbutus to Sayreville Junction, It takes 0.27 hours to arrive.
Arbutus
Arbutus is located in United States.
| GPS Coordinates (DMS) | 39° 15´ 16.3800'' N 76° 41´ 59.8920'' W |
|---|---|
| Latitude | 39.25455 |
| Longitude | -76.69997 |
| Altitude | 46 m |
| Country | United States |
Arbutus Distances to Cities
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |