Distance from Arbutus to Cockeysville
Distance from Arbutus to Cockeysville is 26 kilometers. This air travel distance is equal to 16 miles.
The air travel (bird fly) shortest distance between Arbutus and Cockeysville is 26 km or 16 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arbutus to Cockeysville, It takes 0.03 hours to arrive.
Arbutus
Arbutus is located in United States.
| GPS Coordinates (DMS) | 39° 15´ 16.3800'' N 76° 41´ 59.8920'' W |
|---|---|
| Latitude | 39.25455 |
| Longitude | -76.69997 |
| Altitude | 46 m |
| Country | United States |
Arbutus Distances to Cities
Cockeysville
Cockeysville is located in United States.
| GPS Coordinates | 39° 28´ 52.3920'' N 76° 38´ 37.8960'' W |
|---|---|
| Latitude | 39.48122 |
| Longitude | -76.64386 |
| Altitude | 91 m |
| Country | United States |