Distance from Algonquin to Sandusky
Distance from Algonquin to Sandusky is 471 kilometers. This air travel distance is equal to 293 miles.
The air travel (bird fly) shortest distance between Algonquin and Sandusky is 471 km or 293 miles.
If you travel with an airplane (which has average speed of 560 miles) from Algonquin to Sandusky, It takes 0.52 hours to arrive.
Algonquin
Algonquin is located in United States.
| GPS Coordinates (DMS) | 42° 9´ 56.0880'' N 88° 17´ 39.3000'' W |
|---|---|
| Latitude | 42.16558 |
| Longitude | -88.29425 |
| Altitude | 227 m |
| Country | United States |
Algonquin Distances to Cities
Sandusky
Sandusky is located in United States.
| GPS Coordinates | 41° 26´ 56.1840'' N 82° 42´ 28.6560'' W |
|---|---|
| Latitude | 41.44894 |
| Longitude | -82.70796 |
| Altitude | 183 m |
| Country | United States |
Sandusky Distances to Cities
| Sandusky | Distance |
|---|---|
| Distance from Sandusky to South Euclid | 100 km |
| Distance from Sandusky to Waukesha | 488 km |
| Distance from Sandusky to Pittsburgh | 254 km |
| Distance from Sandusky to Tucson | 2,702 km |
| Distance from Sandusky to Janesville | 540 km |