Distance from Shelbyville to Petersburg
Distance from Shelbyville to Petersburg is 835 kilometers. This air travel distance is equal to 519 miles.
The air travel (bird fly) shortest distance between Shelbyville and Petersburg is 835 km= 519 miles.
If you travel with an airplane (which has average speed of 560 miles) from Shelbyville to Petersburg, It takes 0.93 hours to arrive.
Shelbyville
Shelbyville is located in United States.
| GPS Coordinates (DMS) | 35° 29´ 0.2760'' N 86° 27´ 36.9720'' W |
|---|---|
| Latitude | 35.48341 |
| Longitude | -86.46027 |
| Altitude | 237 m |
| Country | United States |
Shelbyville Distances to Cities
Petersburg
Petersburg is located in United States.
| GPS Coordinates | 37° 13´ 40.5480'' N 77° 24´ 6.9480'' W |
|---|---|
| Latitude | 37.22793 |
| Longitude | -77.40193 |
| Altitude | 22 m |
| Country | United States |
Petersburg Distances to Cities
| Petersburg | Distance |
|---|---|
| Distance from Petersburg to Virginia Beach | 133 km |
| Distance from Petersburg to Beckley | 340 km |
| Distance from Petersburg to Staunton | 179 km |
| Distance from Petersburg to Roanoke | 225 km |
| Distance from Petersburg to Pampa | 2,117 km |