Distance from Secaucus to Providence
Distance from Secaucus to Providence is 249 kilometers. This air travel distance is equal to 155 miles.
The air travel (bird fly) shortest distance between Secaucus and Providence is 249 km= 155 miles.
If you travel with an airplane (which has average speed of 560 miles) from Secaucus to Providence, It takes 0.28 hours to arrive.
Secaucus
Secaucus is located in United States.
| GPS Coordinates (DMS) | 40° 47´ 22.3800'' N 74° 3´ 23.5080'' W |
|---|---|
| Latitude | 40.78955 |
| Longitude | -74.05653 |
| Altitude | 2 m |
| Country | United States |
Secaucus Distances to Cities
Providence
Providence is located in United States.
| GPS Coordinates | 41° 49´ 26.3640'' N 71° 24´ 46.1880'' W |
|---|---|
| Latitude | 41.82399 |
| Longitude | -71.41283 |
| Altitude | -17 m |
| Country | United States |
Providence Distances to Cities
| Providence | Distance |
|---|---|
| Distance from Providence to Boston | 66 km |
| Distance from Providence to Smithfield | 16 km |
| Distance from Providence to Phoenix | 3,671 km |
| Distance from Providence to Virginia | 790 km |
| Distance from Providence to Palmdale | 4,117 km |