Distance from Searcy to Altus
Distance from Searcy to Altus is 697 kilometers. This air travel distance is equal to 433 miles.
The air travel (bird fly) shortest distance between Searcy and Altus is 697 km= 433 miles.
If you travel with an airplane (which has average speed of 560 miles) from Searcy to Altus, It takes 0.77 hours to arrive.
Searcy
Searcy is located in United States.
| GPS Coordinates (DMS) | 35° 15´ 2.3040'' N 91° 44´ 10.5000'' W |
|---|---|
| Latitude | 35.25064 |
| Longitude | -91.73625 |
| Altitude | 82 m |
| Country | United States |
Searcy Distances to Cities
| Searcy | Distance |
|---|---|
| Distance from Searcy to Tulsa | 398 km |
| Distance from Searcy to Starkville | 334 km |
| Distance from Searcy to Farmers Branch | 541 km |
| Distance from Searcy to Dallas | 542 km |
| Distance from Searcy to Oklahoma City | 526 km |
Altus
Altus is located in United States.
| GPS Coordinates | 34° 38´ 17.2680'' N 99° 20´ 2.3280'' W |
|---|---|
| Latitude | 34.63813 |
| Longitude | -99.33398 |
| Altitude | 430 m |
| Country | United States |
Altus Distances to Cities
| Altus | Distance |
|---|---|
| Distance from Altus to Lubbock | 261 km |
| Distance from Altus to Frisco | 285 km |
| Distance from Altus to Santa Fe | 613 km |
| Distance from Altus to Mcalester | 328 km |
| Distance from Altus to Houston | 657 km |