Distance from Petersburg to Albany
Distance from Petersburg to Albany is 678 kilometers. This air travel distance is equal to 421 miles.
The air travel (bird fly) shortest distance between Petersburg and Albany is 678 km= 421 miles.
If you travel with an airplane (which has average speed of 560 miles) from Petersburg to Albany, It takes 0.75 hours to arrive.
Petersburg
Petersburg is located in United States.
| GPS Coordinates (DMS) | 37° 13´ 40.5480'' N 77° 24´ 6.9480'' W |
|---|---|
| Latitude | 37.22793 |
| Longitude | -77.40193 |
| Altitude | 22 m |
| Country | United States |
Petersburg Distances to Cities
| Petersburg | Distance |
|---|---|
| Distance from Petersburg to Virginia Beach | 133 km |
| Distance from Petersburg to Beckley | 340 km |
| Distance from Petersburg to Staunton | 179 km |
| Distance from Petersburg to Roanoke | 225 km |
| Distance from Petersburg to Pampa | 2,117 km |
Albany
Albany is located in United States.
| GPS Coordinates | 42° 39´ 9.2880'' N 73° 45´ 22.4280'' W |
|---|---|
| Latitude | 42.65258 |
| Longitude | -73.75623 |
| Altitude | 50 m |
| Country | United States |
Albany Distances to Cities
| Albany | Distance |
|---|---|
| Distance from Albany Ny to Las Vegas | 3,598 km |
| Distance from Albany Ny to Kingston | 83 km |
| Distance from Albany Ny to Sacramento | 4,011 km |
| Distance from Albany Ny to San Francisco | 4,120 km |
| Distance from Albany Ny to Los Angeles | 3,956 km |