Distance from Oklahoma to Sandy Hills
Distance from Oklahoma to Sandy Hills is 1,437 kilometers. This air travel distance is equal to 893 miles.
The air travel (bird fly) shortest distance between Oklahoma and Sandy Hills is 1,437 km= 893 miles.
If you travel with an airplane (which has average speed of 560 miles) from Oklahoma to Sandy Hills, It takes 1.59 hours to arrive.
Oklahoma
Oklahoma is located in United States.
| GPS Coordinates (DMS) | 35° 0´ 27.9000'' N 97° 5´ 34.3680'' W |
|---|---|
| Latitude | 35.00775 |
| Longitude | -97.09288 |
| Altitude | 332 m |
| Country | United States |
Oklahoma Distances to Cities
| Oklahoma | Distance |
|---|---|
| Distance from Oklahoma to California | 2,021 km |
| Distance from Oklahoma to New York | 2,121 km |
| Distance from Oklahoma to Texas | 426 km |
| Distance from Oklahoma to Ohio | 1,385 km |
| Distance from Oklahoma to Colorado | 920 km |
Sandy Hills
Sandy Hills is located in United States.
| GPS Coordinates | 40° 34´ 51.8160'' N 111° 51´ 2.7720'' W |
|---|---|
| Latitude | 40.58106 |
| Longitude | -111.85077 |
| Altitude | 1459 m |
| Country | United States |