Distance from Oklahoma City to Sandy Hills
Distance from Oklahoma City to Sandy Hills is 1,378 kilometers. This air travel distance is equal to 856 miles.
The air travel (bird fly) shortest distance between Oklahoma City and Sandy Hills is 1,378 km= 856 miles.
If you travel with an airplane (which has average speed of 560 miles) from Oklahoma City to Sandy Hills, It takes 1.53 hours to arrive.
Oklahoma City
Oklahoma City is located in United States.
| GPS Coordinates (DMS) | 35° 28´ 3.2160'' N 97° 30´ 59.1480'' W |
|---|---|
| Latitude | 35.46756 |
| Longitude | -97.51643 |
| Altitude | 395 m |
| Country | United States |
Oklahoma City Distances to Cities
| Oklahoma City | Distance |
|---|---|
| Distance from Oklahoma City to Dallas | 305 km |
| Distance from Oklahoma City to Ponca City | 143 km |
| Distance from Oklahoma City to Owasso | 174 km |
| Distance from Oklahoma City to Memphis | 680 km |
| Distance from Oklahoma City to Houston | 664 km |
Sandy Hills
Sandy Hills is located in United States.
| GPS Coordinates | 40° 34´ 51.8160'' N 111° 51´ 2.7720'' W |
|---|---|
| Latitude | 40.58106 |
| Longitude | -111.85077 |
| Altitude | 1459 m |
| Country | United States |